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Inequality Calculator

A linear inequality compares a linear expression to a constant using <, ≤, >, or ≥ instead of an equals sign, and its solution is a range of values rather than a single number. This calculator solves inequalities of the form ax + b [operator] c for x, correctly flipping the inequality sign when dividing by a negative coefficient.

आख़िरी बार समीक्षा: 2026-07-07

Understanding the sign-flip rule

The sign of the coefficient a determines whether the inequality symbol stays the same or reverses when isolating x, as shown below.

Sign of aEffect on inequality symbolExample
a > 0 (positive)Symbol unchanged2x < 8 → x < 4
a < 0 (negative)Symbol reverses (< becomes >, ≤ becomes ≥, etc.)−2x < 8 → x > −4
a = 0Reduces to a true/false statement about constants only0x + 3 < 11 → always true (all real numbers)
  • When a = 0, the result is either 'All real numbers (always true)' or 'No solution (always false)', because the inequality no longer depends on x at all.
  • The boundary value shown is the point at which the linear expression ax + b exactly equals c; whether that boundary itself is included in the solution depends on whether the inequality is strict (<, >) or inclusive (≤, ≥).
  • This calculator solves one-variable linear inequalities only. Compound inequalities (e.g. 3 < 2x + 1 < 9) and inequalities involving x² or higher powers require different solution methods.

What is a linear inequality?

A linear inequality is a mathematical statement comparing a linear expression (a variable raised only to the first power, with a coefficient and constant) to another value using an inequality symbol: less than (<), less than or equal to (≤), greater than (>), or greater than or equal to (≥). Unlike a linear equation, which typically has one solution, a linear inequality usually has infinitely many solutions — every value of x that makes the statement true.

This calculator solves inequalities in the form ax + b [operator] c, where a is the coefficient of x, b is a constant added on the left side, and c is the value being compared against on the right. Solving means isolating x on one side, producing a result such as x < 4, meaning every value less than 4 satisfies the original inequality.

The single most important rule that distinguishes solving inequalities from solving equations is this: multiplying or dividing both sides of an inequality by a negative number reverses the direction of the inequality symbol. This calculator applies that rule automatically based on the sign of the coefficient a.

How to use this inequality calculator

  1. Enter the coefficient of x (a) — the number multiplying x on the left side of the inequality.
  2. Enter the constant (b) — the number added to ax on the left side. Use 0 if there is no constant term.
  3. Select the inequality symbol: <, ≤, >, or ≥.
  4. Enter the value on the right side (c). Read the solution, expressed as x [symbol] boundary value; the sign flips automatically if a is negative.

The method for solving linear inequalities

ax + b < c → x < (c − b) ÷ a (if a > 0)
ax + b < c → x > (c − b) ÷ a (if a < 0, symbol flips)
Example: 2x + 3 < 11 → 2x < 8 → x < 4
Example (negative a): −2x + 3 < 11 → −2x < 8 → x > −4

Solving ax + b [op] c for x follows the same algebraic steps as solving an equation: subtract b from both sides, then divide both sides by a. Worked example: solve 2x + 3 < 11. Subtract 3 from both sides: 2x < 8. Divide both sides by 2 (a positive number, so the inequality direction is unchanged): x < 4.

When the coefficient a is negative, dividing both sides by it reverses the inequality symbol. Worked example: solve −2x + 3 < 11. Subtract 3: −2x < 8. Divide both sides by −2 and flip the symbol: x > −4 (not x < −4). This sign-flip rule is the single most common source of errors when solving inequalities by hand.

A special case arises when a = 0: the inequality reduces to a constant comparison, such as 3 < 11, which is either always true (in which case the solution is 'all real numbers') or always false (in which case there is 'no solution'), independent of x.

Common mistakes

  • Forgetting to flip the inequality symbol when multiplying or dividing both sides by a negative number — this is the single most common error when solving inequalities.
  • Treating ≤ and < (or ≥ and >) as interchangeable — the distinction matters for whether the boundary value itself is included in the solution set.
  • Applying equation-solving intuition without checking the sign of the coefficient — an inequality with a negative coefficient does not solve the same way as a positive one.
  • Assuming an inequality always has a numeric boundary — when the coefficient of x is 0, the result collapses to 'always true' or 'always false' with no boundary value at all.

अक्सर पूछे जाने वाले सवाल

How do you solve a linear inequality?

Isolate the variable using the same steps as solving an equation — add or subtract to move constants, then multiply or divide to remove the coefficient — but reverse the inequality symbol whenever you multiply or divide both sides by a negative number. For 2x + 3 < 11: subtract 3 to get 2x < 8, then divide by 2 to get x < 4.

Why does the inequality sign flip when multiplying by a negative number?

Multiplying or dividing by a negative number reverses the order of values on the number line — for example, 2 < 5, but multiplying both sides by −1 gives −2 and −5, and −2 is actually greater than −5. To keep the statement true, the inequality symbol must reverse: −2 > −5.

What does 'no solution' mean for an inequality?

'No solution' occurs when the coefficient of x is zero and the resulting constant comparison is false — for example, 0x + 3 > 11 simplifies to 3 > 11, which is never true regardless of x. In this case, no value of x can satisfy the original inequality.

What is the difference between < and ≤?

< (strictly less than) excludes the boundary value itself from the solution, while ≤ (less than or equal to) includes it. For x < 4, the value 4 is not a solution; for x ≤ 4, the value 4 is a solution. This distinction is visually represented on a number line by an open circle (<, >) versus a closed/filled circle (≤, ≥) at the boundary.

How do you check the solution to an inequality?

Substitute a test value from your solution range back into the original inequality and confirm it holds true, and optionally test a value outside the range to confirm it does not. For the solution x < 4 to 2x + 3 < 11, testing x = 0 gives 2(0) + 3 = 3 < 11 ✓, while testing x = 5 (outside the range) gives 2(5) + 3 = 13, which is not < 11, confirming the boundary is correct.

संदर्भ

  1. NIST Digital Library of Mathematical Functions (DLMF), §1.2 Elementary Algebra: Inequalities. dlmf.nist.gov.
  2. Sullivan M. Algebra and Trigonometry. 11th ed. Pearson, 2019. (Linear inequalities in one variable.)
  3. Lial ML, Hornsby J, Schneider DI, Daniels CJ. College Algebra. 13th ed. Pearson, 2017.

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